Python information and short questions megathread.

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huhu: Feb 24, 2006

I've got a Python function that I've added throughout a script I want to run autonomously. Its purpose is to print various log information to a txt file. What would the bests way to log any errors that might occur to the same file?

code:

def print_log(text_to_log):
    """
    Print text to log.txt file and command line
    """
    print(text_to_log)
    f = open("log.txt", "a")
    f.write(text_to_log + "\n")
    f.close()

# ¿ Mar 1, 2017 17:26

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# ¿ May 8, 2024 04:55

huhu: Feb 24, 2006

a witch posted:

Look into the logging module, it has a decent tutorial.

If you want to write messages to the console and a file at the same time, you'll want a logger with a FileHandler and a StreamHandler attached.

E: I'm on a phone so can't type code, here's the basic tutorial https://docs.python.org/3/howto/logging.html

Awesome thanks.

Another question - I have a script running that uploads files to dropbox. If the internet goes down mid upload, I get a MaxRetryError. Trying the following doesn't work though

code:

try:
    # upload file
    return True
except MaxRetryError:
    return False

what should I be putting instead?

# ¿ Mar 1, 2017 20:21

huhu: Feb 24, 2006

Eela6 posted:

What do you want to happen?

I want the function to return false. However, with that code I'm getting "NameError: global name 'MaxRetryError' is not defined".

# ¿ Mar 1, 2017 20:25

huhu: Feb 24, 2006

Zero Gravitas posted:

Anyone got any recommendations for a method of creating animations (avi/mpeg/mp4) from a bunch of .png files? I've inherited a collection of code that does this with cv2 (I think) but its awfully put together and throws lots of errors with the l/w/h parameters.

Virtualdub is pretty awesome. Just select fps, compression method, and any other settings and you get a nice video.

# ¿ Mar 5, 2017 01:14

huhu: Feb 24, 2006

I have some Flask code:

code:

    {% for image in gallery %}
        <img src ="{{ url_for('static', filename = 'img/image') }}">
    {% endfor %}

gallery is a list containing a bunch of filenames (i.e. "a.jpg", "b.jpg") How do I pass image (i.e. "a.jpg") from the for loop into 'img/image' so that it appears as 'img/a.jpg' instead?

Edit - Is this the best way?

code:

    {% for image in gallery %}
        <img src ="{{ url_for('static', filename = 'img/')}}{{ image }}">
    {% endfor %}

huhu fucked around with this message at 03:14 on Mar 7, 2017

# ¿ Mar 7, 2017 03:10

The Something Awful Forums > Discussion > Serious Hardware/Software Crap > The Cavern of COBOL > Python information and short questions megathread.

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