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shrughes
Oct 11, 2008

(call/cc call/cc)
Just return them in some object that contains two fields.

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shrughes
Oct 11, 2008

(call/cc call/cc)

Aleksei Vasiliev posted:

code:
public int mod(int a, int b) {
	return ((a % b) + b) % b;
}

That doesn't work if (a % b) + b overflows.

You can always cast to long and do (a + 0x100000000l * b) % b.

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