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#95 A's name has 6 syllables and 0 vowel sounds. B's name has 5 syllables and 1 vowel sound. C's name has 7 syllables and 0 vowel sounds. D's name has 8 syllables and 2 vowel sounds. The name with 2 vowels is not A (#1) or C (#2) or B (#6) so it has to be D. By #5 and #6, the name with 2 vowels can't have 5, 6, or 7 syllables, and by the un-numbered premise it can have up 8 and won't have the same number as the other names. So D's name has 8 syllables. By #2, C's name has at least 7 syllables, and because we already have a name with 8 syllables, it has to have exactly 7. By #3, C's name doesn't have exactly 1 vowel, and we already have a name with 2 vowels, so C's name has to have 0 vowels. By #4, B's name has to have 1 vowel because it can't have the same number of vowels as C. By #6, B's name isn't the one with 6 syllables, so it has to have 5 syllables. By process of elimination, A's name has 6 syllables and 0 vowel sounds.
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Jan 14, 2021 17:20
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#95 A: 0 vowels, 6 syllables B: 1 vowel, 5 syllables C: 0 vowels, 7 syllables D: 2 vowels, 8 syllables #1,#2, and #6 tell us only D can have two vowel sounds. #5 & #6 let us know D cannot be the 5-,6-, or 7-syllable name. By #4, A must have zero vowel sounds, since if A had one, B & C would both be zero. By #6 and #2, only A can have 6 syllables, and that means only B can have 5 syllables. That means only C's name can have 7 syllables, and by #3 (and #5), it thus has zero vowel sounds, and B has one vowel sound. While D's name could have 8, or anywhere from 1 to 4 syllables, it's implied by the problem that it has 8.
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Jan 14, 2021 19:56
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Correct! Puzzle #96: Transportation In Knowhey Land There are three principal means of transportation in the land of Knowhey: by foot, by private autojet, and by public airfoil transit. Four Knowheyans commute regularly to the metropolitan center to work, and to attend cultural and sporting events. As is traditional on the planet, the four dress in bright, solid colors. The Knowheyan interpreter is explaining to the visitors the method each uses to travel to the metropolitan center and the color in which each is attired. From the statements below, determine the method of transportation and dress color of each of the four Knowheyans. 1. Of the four, no two travel by foot or by private autojet. 2. Neither A nor B, who do not travel by private autojet, wears red. 3. The one who wears red does not travel by foot. 4. Neither the one who wears blue nor the one who wears green travels by private autojet. 5. Neither C, who does not travel by public airfoil transit, nor D wears orange. 6. D, who does not wear red, does not travel by foot. 7. The one who wears green, who is not B, does not travel by public airfoil transit.
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Jan 15, 2021 21:14
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#96 A wears green and travels by foot B wears orange and travels by public airfoil C wears red and travels by private autojet D wears blue and travels by public airfoil By #1, we have one who goes by foot, one who goes by jet, and two who go by public airfoil. By #4 and #7, the green-wearer has to go by foot. D wears blue, since they don't wear orange (#5) or red (#6) and they don't travel by foot so they're not green (#6 again). D has to travel by public airfoil, since by #4 they don't use a private jet. By #2, neither A nor B goes by private jet, so the jet-setter has to be C. By #4 and #5, C has to wear red. By #7, B doesn't wear green, so they wear orange. By elimination, A wears green, and we already know they go by foot. Also by elimination, B has to travel by airfoil.
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Jan 15, 2021 21:40
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There's a problem with the puzzle as stated: We are told that each of the four dresses in bright colors, but we aren't told what those colors are. Clues 3, 4 and 7 reference "the one who wears" red, blue and green, so we can assume that there is, in fact, exactly one person wearing each of those colors. But all we know about the fourth color is that C and D are NOT wearing orange. Either of them could be wearing, say, yellow instead. And in that case the puzzle no longer has a unique solution. Assuming that this is an oversight, and that there is in fact a person wearing orange: A wears green and travels by foot. B wears orange and travels by public airfoil transit. C wears red and travels by private autojet. D wears blue and travels by public airfoil transit. Proof: 1. By clues 4 and 7, Green does not travel by private autojet or by public airfoil transit. Therefore Green travels by foot. 2. By clue 4, Blue does not travel by private autojet. By clue 1, no two people can travel by foot, and we already know Green does, so Blue can't. Therefore Blue must travel by public airfoil transit. 3. By clues 5 and 6, D does not wear orange or red. Also by clue 6, D does not travel on foot, and we already know Green does just that, so D can't be Green. So D must be Blue. 4. By clue 2, B does not travel by private autojet. By clue 7 B is not Green; we know Green travels by foot, and by clue 1 at most one person travels by foot, so B does not travel by foot. Therefore B travels by public airfoil transit. 5. By clue 2, B is not Red. By clue 7, B is not Green. We already know Blue is D, so B must be Orange. 6. By clue 2, A is not Red. We already know Blue and Orange are D and B respectively, so A must be Green. 7. Since A, B and D are Green, Orange and Blue, C must be Red. 8. By clue 5, C does not travel by public airfoil transit. By clue 3, Red (who is C) does not travel on foot. Therefore, C must travel by private autojet.
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Jan 15, 2021 23:32
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Correct! Puzzle #96: The Game Of Gulf Gulf is a popular game on Knowhey. It is played by hitting a small ball over long distances. The objective is to put the ball into a small hole with a minimum number of hits. The name of the game is derived from the land's terrain, which includes many extended inlets, or gulfs, over which balls must travel. In an attempt to explain the game, the Knowheyan interpreter is describing, in negative Knowheyan fashion, the results of a game played by four inhabitants, A, B, C, and D. Each lost a different number of balls, and no player lost fewer than one or more than four. 1. The player with the highest score did not lose the fewest or the most balls. 2. The one with the second-lowest score, who was not D, did not lose more than three balls. 3. The player with the lowest score did not lose four balls. 4. The one with the highest score lost more than two balls. 5. B did not lose more than three balls or fewer than two balls. 6. The player who lost only one ball was not the one with the lowest score. 7. Neither D, who was not the one with the highest score, nor A, lost more than three balls. What was the scoring order of the four players and how many balls did each lose?
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Jan 18, 2021 23:57
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#96: From lowest to highest: D got the lowest score and lost 2 balls. A got the second-lowest score and lost 1 ball. C got the second-highest score and lost 4 balls. B got the highest score and lost 3 balls. The player with the highest score didn't lose 1 or 4 balls (#1) and lost more than 2 balls (#4) so they lost exactly 3. Neither B (#5) nor D nor A (#7) lost more than 3 balls, which means C lost 4 (the most) balls. C didn't get the highest score (#1), the lowest score (#3), or the second-lowest score (#2) so they got the second-highest score. The player with the lowest score lost 2 balls (#6) and the player with the second-lowest score lost 1 ball. D did not get the highest score (#7) or the second-lowest (#2), and we know C got the second-highest, so D got the lowest score. B lost either 2 or 3 balls (#5) and we know D lost 2 balls, so B lost 3 and therefor got the highest score. A got the second-lowest score by process of elimination. This satisfies #2, #6, and #7.
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Jan 19, 2021 00:30
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Correct! Puzzle #98: Leisure Time The advanced technology in the land of Knowhey affords the inhabitants considerable leisure time. Four Knowheyans, A, B, C, and D, each enjoy one of four leisure time activities: boating, music, reading, and gulf (a game that involves hitting a small ball long distances, frequently over inlets, or gulfs, that extend far inland). The time from dawn to dusk is referred to as SP (Solar Period) and is measured in hundredths of SP. No two of the four spend the same amount of time in their leisure interests. In response to a question regarding the four Knowheyan's leisure time and interests, the interpreter makes the following statements: 1. Neither A nor C plays gulf or is the one who spends .75 SP in leisure time interests. 2. The one who spends .6 SP in leisure time does not like boating. 3. The one who spends .9 SP in leisure time interests does not enjoy boating or music. 4. D does not play gulf, nor does A enjoy reading. 5. The one who enjoys boating is not the one who spends .5 SP in leisure time interests. 6. B does not spend .9 SP in leisure time interests. 7 The gulfer does not spend .5 SP in leisure time interests. Can you determine which Knowheyan enjoys which leisure time interest and the amount of time each devotes to the activity?
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Jan 21, 2021 09:35
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Arrange the provided information. A != gulf A != reading A != .75 B != .9 C != gulf C != .75 D != gulf Boating != .5 Boating != .6 Boating != .9 Music != .9 Gulf != .5 Boating = .75 by elimination, thus A and C != boating. A = music by elimination. C != gulf, music or boating, so C can only = reading. B is now the only possible gulfer, so D is the boater with .75. The rest is elementary: A - Music - .5 B - gulf - .6 C - Reading - .9 D - Boating - .75 Aesculus fucked around with this message at 22:13 on Jan 21, 2021 |
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Jan 21, 2021 11:31
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#98 : A - Music, 0.5 SP B - Gulf, 0.6 SP C - Reading, 0.9 SP D - Boating, 0.75 By 1 & 4, B plays gulf. By 6 & 7, B must spend either .75 or 0.6 SP. By 2, 3, & 5, the boater spends 0.75, meaning B spends 0.6. By this & 3, the reader spends 0.9 SP, leaving the musician with 0.5. By 1, D must be the boater. By 1 & 4, A must be the musician, and C is the reader.
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Jan 21, 2021 13:55
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#98: A enjoys music and spends .5 SP on it. B enjoys gulf and spends .6 SP on it. C enjoys reading and spends .9 SP on it. D enjoys boating and spends .75 SP on it. First let's establish the possible time periods are .5 SP (#5, #7), .6 SP (#2), .75 SP (#1), and .9 SP (#3, #6). Either B or D plays gulf (#1), and D does not play gulf (#4), which means it's B. .9 SP is spent either playing gulf or reading (#3), but B plays gulf and does not spent .9 SP on it (#6), so .9 SP is spent reading. The one who enjoys boating does not spend .5 SP (#5) or .6 SP (#2) and the .9 slot is already taken, so boating takes .75 SP. B the gulfer has to spent .6 SP, because of the previous two deductions as well as #7 saying they don't spent .5 SP. Music is the only activity we don't have a time for, so it gets .5 SP. Either B or D spends .75 SP on their thing (#1) and we know it's not B, so it's D, and we know boating is the .75 SP activity. A doesn't read (#4) and music is the only activity left, which we know takes .5 SP. C is the only one left, so they read and spend .9 SP on it.
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Jan 21, 2021 17:38
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Correct, all of you! And now, we move on to the next section: Would Martians Lie? This section has a few shorter puzzles before the bigger ones so I'll do the first four in one post. Puzzle #99: The Martian Rub After his spaceship landed on Mars, astronaut Jonathan Mark disembarked and approached the first Martian he saw. "Am I headed toward the geological dig?" He asked. The Martian rubbed his stomach. Mark knew that Martians could understand some Earth-talk, but were not able to speak it. And astronaut Mark, like so many Earthlings, could neither speak nor understand Martian gestures. He didn't know whether rubbing the stomach meant yes or no. But by asking one additional question, Mark was able to find out. What was that question? Puzzle #100: Stone Stew After astronaut Mark got to the dig, he collected rock specimens to take back to the Earth scientists. He packed the rocks into three sacks: One for igneous rocks, one for sedimentary, and one for metamorphic. But, rushing to return to the aircraft before his portable oxygen ran out, he mislabeled all the sacks. How many rocks did he have to take out of how many sacks in order to find out what was in each one? Puzzle #101: Friend or Foe? Among the inhabitants of Mars were various kinds of creatures. One type was friendly to visitors from Earth and always told the truth. Another was hostile and always lied to Earthlings. The problem was that the astronauts couldn't tell the difference between them. "Are you a truth-teller?" astronaut John Armstrong asked a striped Martian he met on the way to the dig. "He'll say 'Yes'," commented a spotted Martian who was nearby. "But he'll be lying." Who was the truth-teller, the striped Martian or the spotted one? Puzzle #102: How Many Liars? Molly Ride, pilot of the spacecraft, knew that some Martians were truth-tellers, and some were not. So when she came face to face with three of them, she asked, "Are you truth-tellers?" The finned Martian answered her by rubbing his stomach. His friend, a tall martian with feathered ears, told her that the finned Martian had said he was a truth-teller. However, the other Martian, who had horns, said the finned Martian was lying. How many of these Martians were liars?
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Jan 23, 2021 02:34
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Ah, back to puzzles I can answer! #99: "Are you a Martian?" Same gesture = yes, you're heading towards the dig. Different gesture = no, you were going the wrong way. #100: One. If all the sacks are guaranteed to be mislabeled (no sack is correctly labeled), then you take out rocks from sack A and put the correct label on it. Now, let's say the label you just moved was on sack B. Since sack C was also mislabeled, there's only one place the label on sack C can go and be correct; that's sack B. Finally, you move sack A's wrong label to sack C and all the rocks are correctly labeled. #101: Beats me. If the spotted Martian's statement is taken as two separate statements then the spotted martian must be telling the truth. If they were the liar they'd say the striped martian would say 'no'. #102: One Martian is lying. Basically, we can't know what the finned martian said, but if they had said "I'm a liar", they would have been a liar telling the truth, which is impossible. So they had to say they are a truth teller. So, the martian with the feathered ears is never lying. If the finned martian is lying, the horned martian is telling the truth and vice versa.
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Jan 23, 2021 04:14
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#99: It could be "Are you a Martian?" or something similar where this guy knows the answer is 'yes' and wants to see how the Martian responds. #100: Assuming each sack contains only rocks of the same type, one rock out of each of two sacks would suffice. #101: If you take what the spotted Martian says as two statements, then the spotted Martian would be telling the truth. If they were lying then the two statements would contradict each other. #102: Let's break this down. Finned Martian says "I am a truth-teller." Tall Martian says "Finned Martian claims he is a truth-teller." Horned Martian says "Finned Martian is lying." Tall Martian is telling the truth no matter what, since his observation is about what the Finned Martian claims and not the truth of the statement. If the Finned Martian is telling the truth, then the Horned Martian is lying. If the Finned Martian is lying, the Horned Martian is telling the truth. Therefor there are 2 truth-tellers.
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Jan 23, 2021 07:24
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I know it didn't ask, but how does the astronaut in #99 know the Martian's not lying?
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Jan 24, 2021 05:09
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Kangra posted:I know it didn't ask, but how does the astronaut in #99 know the Martian's not lying? If we backtrack from the later questions, perhaps the most appropriate question to ask would be are you a truth-teller? - because a truth-teller would make the yes gesture because it's true and the liar would make the yes gesture because it's a lie. Either way, you know whether the stomach rub means yes or if yes is a different gesture, while also solving the problem Kangra brings up.
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Jan 24, 2021 06:00
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#99 says that Martians are unable to speak Earth-talk, which is why they rub their stomachs. Yet suddenly in #101 and #102 they're speaking English just fine. Clearly the author of this book is lying and we can't solve anything. Also here's an alternate solution to #102 that the author probably didn't think of: The finned martian literally said yes or no, so the second one is lying about what the first one said. The horned says finned is lying so one of them must be a liar, making two liars. Second alternate solution:Finned one is answering whether or not they're ALL truthtellers. If he said yes then Ears is telling the truth, making one liar (and it's Fin). If he said no then Ears is lying because Fin didn't specify whether he himself was telling the truth or not, taking us back to two liars (but we know Fin is telling the truth with this possibility). Problem is unsolvable. whitehelm fucked around with this message at 17:16 on Jan 24, 2021 |
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Jan 24, 2021 16:46
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Quackles and IMJack have 101 and 102 right, Quackles has 100 right, but nobody got 99 right, technically-but I'll allow it. The correct answer was Mark rubbed his stomach and asked 'did you do this?', and whatever the Martian did in reply would mean yes.. Puzzle #103: The Search for Doman This was astronaut José Perez's fourth visit to Mars, and he had learned to speak Martian. He wanted to find his Martian friend Doman, but in order to locate him he had to know what group Doman belonged to. The three groups in the area were: Uti, Yomi, and Grundi. The Uti always told the truth. The Yomi always lied. The Grundi sometimes told the truth but sometimes lied. Perez needed information. Three Martians, Aken, Bal and Cwos, each of who belonged to a different group, agreed to help him. He asked each one of them two questions: What group do you belong to? What group does Doman belong to? Aken said: I am not a Uti. Doman is a Yomi. Bal said: I am not a Yomi. Doman is a Grundi. Cwos said: I am not a Grundi. Doman is an Uti. What group does Doman belong to?
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Jan 25, 2021 07:36
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#103 Doman is an Uti. Aken's statement of not being an Uti would be truthful from a Yomi, and false from an Uti; Aken is necessarily a Grundi. (Also their second statement is false, since there must be one Uti in the group, and thus only one truthful statement about Doman.) Since Cwos cannot be a Grundi, their first statement would be true from a Yomi, an impossiblity. That means Cwos must be of the Uti, and so is Doman.
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Jan 25, 2021 08:45
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#103 Doman is Uti. Aken has to be telling the truth about not being an Uti, so they must be Grundi. Of the other two, one has to be always telling the truth and the other always lying. If Bal is telling the truth about not being Yomi, Bal would be Uti and therefor Cwos would be Yomi. But then Cwos would be telling the truth about not being Grundi, and if they're Yomi then nothing they say can be true. Cwos has to be Uti, which means they're telling the truth about Doman being Uti.
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Jan 25, 2021 18:05
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#103 OK, so let's start with Aken. If Aken is not an Uti and says as much, well, they can't be an Uti (an Uti would say they are) and they can't be a Yomi (they would be telling the truth and Yomis don't). So Aken must be a Grundi, and their first statement is truthful. So: is their second statement a lie? If it is not, then Doman is a Yomi, but no one else said Doman is a Yomi. As there is at least one Uti in the other two, that would contradict the Uti's assessment. So Doman is not a Yomi, and Aken's second statement is a lie. So now consider Cwos. Cwos is either an Uti or a Yomi. They are not a Grundi (as Aken is one), which means their first statement is true. So Cwos can't be a Yomi, because they always lie. This means that Cwos's second statement is also true and Doman is an Uti.
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Jan 26, 2021 00:13
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Correct, all three of you! Puzzle #104: Martian Mystery There was trouble from the Grundi. One of them had damaged the spaceship by healing a rock at it. The astronauts couldn't figure out what the Grundi had to gain by their hostile act. Was it just vandalism done out of sheer spite? Or perhaps not everyone on Mars was happy to see the Earthlings return. The Martian police chief brought in five Grundi for questioning. Like all Grundi, they sometimes told the truth and sometimes lied. The suspects each made three statements, two of which were true and one of which was false, and the guilty one was revealed. Zum said: -I am innocent. -I have never used a rock to destroy anything. -Tset did it. Uk said: -I did not do the damage. -The Earthman's vehicle is on Grundi space. -Yan is not my friend. Pala said: -I am innocent. -I never saw Yan before. -Tset is guilty. Tset said: -I did not throw the rock. -Yan did it. -Zum did not tell the truth when he said I did it. Yan said: -I am innocent. -Uk is guilty. -Pala and I are old friends. Who was the culprit?
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Jan 27, 2021 06:12
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#104: Uk is the culprit. Two suspects say Tset is guilty, so let's start by evaluating Tset's statements. If Tset-1 is false, then Tset-2 and Tset-3 are also false. But the rules say only 1 of the 3 statements can be false. This means Tset-1 is true. Tset-1 being true means Zum-3 and Pala-3 are both false, so the other statements by Zum and Pala have to be true. Pala-2 being true means Yan-3 is false. So Yan's other statements are true, and Yan-2 says Uk is guilty.
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Jan 27, 2021 08:43
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#104 Anyone who says that they are innocent and someone else is guilty didn't do it. If they had, then both statements would be a lie, which is impossible. Zum, Pala, Tset, and Yan all claim they didn't do it and someone else did, so they're innocent. So Uk did it.
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Jan 27, 2021 08:59
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Correct! Next we move onto Planetary Crossings, which... okay, I'll admit, you'll probably have heard variations on these puzzles before. There's only four, I'll put them all together. Puzzle #105: Tsientsien Don't Eat Jonathan Mark gathered three specifimens of Martian plant and animal life to bring back to Earth: a garble, a farfel, and a tsientsien. But Mark was worried. His vehicle for local travel was not big enough to hold more than himself and one specimen. Mark knew that garbles will eat farfels if given half a chance, and farfels will eat tsientsien. Garbles, however, don't eat tsientsien, and tsientsien don't eat. All the other astronauts were away from the ship. How could Mark transport the garble, the farfel, and the tsientsien one at a time so that they would all be safe? Puzzle #106: The Gravity on Mars Two Martians and two Earthlings traveling together came to a canal. As a result of the gravity on Mars, the earthlings each weighed one hundred pounds and the Martians fifty pounds. The watercraft would hold no more than one hundred pounds. How did they all cross the canal? Puzzle #107: Rockfall After being harassed during important experiments, three Earthlings were taking three law-breaking Grudni to the authorities. Suddenly they heard the thunderous roar of a rockfall, and they knew they were facing sure death unless they crossed to the other side of the canal. The portable watercraft they carried with them would hold only two passengers, regardless of weight. At no time could there be more Grundi on either side of the water than Earthlings or the Grundi would overpower the Earthlings and steal the pulleys and ropes needed to travel the hazardous area. How could they all cross the water safely? Puzzle 108: Fins and Feathers Hostile members of the Uni, Grundi, and Yomi groups were traveling to a conference. There were two members from each group, one finned and one feathered. The finned Martian was much stronger, and had to protect her feathered friend. Never could a feathered Martian be left alone with a finned Martian of another group. The only time a feathered Martian was safe with the finned Martian of another group was when the feathered Martian of that group was also present. The trip was quiet until they came to a deep ravine. The only way to cross it was by swinging across on a rope. But the rope was only strong enough to hold two of them. And it wasn't heavy enough for them to swing it back over the ravine without someone to weigh it down. How did they all cross the ravine?
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Jan 31, 2021 09:46
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#105 Go across with the farfel, come back alone. Cross with either of the other specimens, come back with the farfel. Leave the farfel at the start and cross with the remaining specimen, then come back alone, and finally cross with the farfel for the last time. #106 The two Martians cross together. One comes back alone. One of the Earthlings crosses by themself. The other Martian comes back alone. Both Martians cross together again, one comes back alone, the remaining Earthling crosses alone, and the other Martian comes back alone. Both Martians cross together for the last time. #107 This is assuming a Grundi can be forced to cross alone in the boat without causing problems as long as there are Earthlings on both sides. Earthling-1 and Grundi-1 cross together. Earthling-1 stays on the far side and Grundi-1 returns alone. Earthling-2 and Grundi-1 cross back over. Grundi-1 stays with Earthling-1 and Earthling-2 returns alone. Earthling-2 and Grundi-2 cross together. Earthling-2 stays and Grundi-2 returns alone. Grundi-2 and Grundi-3 cross together. Grundi-3 returns alone. Grundi-3 and Earthling-3 cross together for the last time. #108 Any one pair of same-tribe Martians makes the crossing, then the feathered member of the pair stays on the far side while the finned one returns alone. A second same-tribe pair crosses, and the finned member of that pair comes back alone. The same for the third same-tribe pair, the finned one returning alone. Now any two finned Martians can make the crossing. One returns to the first side alone, and then they and the remaining finned Martian make the final crossing together. https://twitter.com/trouteyes/status/887785300507987974 And the wolf stares at the pile of cabbages wishing they had some delicious goats to eat.
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Feb 1, 2021 05:14
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#105: I think the astronaut would simply give up. Who would farfels bear, to groan and sweat onto a weary spaceship, but that the dread of garbles eating them, puzzles the will, and makes us rather bear those plants we have, than fly with those we know not of? Thus logic does make cowards of us all.
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Feb 2, 2021 06:52
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Correct! Onto the final section, we're almost done with the book, but we need to deal with some Martian Mischief before we finish. Puzzle #109: Flying Teams Martians don't need to develop airplanes as a means of moving through the air. Most feathered Martians can fly easily. Every few lunars, feathered Martians from the various groups participate in a tournament which are the best fliers of the planet. This luanr, teams of two feathered Martians from three groups are competing: 1. One team is from the Uti, one from the Grundi, and one from the Yomi. 2. Each team is made of one female and one male. 3. The female participants are Xera, Wora, and Teta. 4. The males are called Vel, Pyi, and Rir. 5. Despite her daring feats in the air, TEta has never been away from home before the contest. 6. Xera and Rir had never met before the tournament. 7. Xera will be visiting Pyi's group when the Yomi go on a special excursion to that part of the planet. 8. Pyi admires Teta's colorful feathers, as well as her ability to soar, and once watched her and her teammate in the territory of the Grundi. If the winners are members of the Uti group, what are the names of the best fliers?
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Feb 6, 2021 16:00
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#109 Per 5 and 8, Teta is on the Grundi team. Also per 8, Pyi can't be her teammate. Per 7, Xera is on the Yomi team and Pyi is not; therefore, Pyi is on the Uti team. Per 6, Xera and Rir are probably not on the same team, which leaves Vel as the male participant of the Yomi team. Teta and Xera are on the Grundi and Yomi teams respectively, which leaves Wora on the Uti team; Pyi and Vel are on the Uti and Yomi teams, leaving Rir on the Grundi team. In summary, the teams are: Teta/Rir on the Grundi team, Xera/Vel on the Yomi team, and Wora/Pyi on the Uti team. That said, the answer depends on how you interpret the third and final sentences of the puzzle. The "best fliers" could be all of the participants or just the Uti team, i.e. Wora and Pyi.
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Feb 6, 2021 20:46
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#109 Teta has never been away from home (#5) but Pyi has seen Teta fly in Grundi territory (#8) so Teta is Grundi. Pyi is not Teta's teammate (#8) and he is not Yomi (#7) so he is Uti. #7 says Xera is Yomi. Wora is the only female unaccounted for so she is Uti. Wora and Pyi are the Uti group and therefor the best fliers. Not that it matters, but Rir is Grundi because he's not Xera's teammate, and Vel is Yomi by elimination.
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Feb 6, 2021 22:32
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Correct! Puzzle #110: Spaceship Crew Kim Jones, Jan Robinson, and Pat Smith are the officers of the spaceship. They serve as the craft's pilot, engineer, and biochemist, though not necessarily in that order. Because they have difficulty with Martian names, they nickname the three Martians who work with them Jones, Smith, and Robinson. 1. Robinson is a Yomi. 2. Jones doesn't speak any language other than Martian. 3. All Martian linguists are Uti. 4. The Martian who serves as interpreter respects the Martian who's name is the same as the biochemist's. 5. The Martian whose name is the same as the biochemist is a Grundi. 6. Jan Robinson beat the engineer at chess. Who is the pilot?
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Feb 8, 2021 16:20
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#110 Jan Robinson is the pilot. Neither Martian Robinson nor Martian Jones is the interpreter, so it has to be Martian Smith (#1-4). Martian Jones is the Grundi since M-Robinson is Yomi (#1) and M-Smith is Uti (#3). Kim Jones is the biochemist (#5). Jan Robinson is not the engineer (#6) so they have to be the pilot.
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Feb 8, 2021 17:58
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#110 Jan Robinson By #1, Robinson is a Yomi. By #5, the Martian named after the biochemist is a Grundi, meaning Robinson is not the biochemist. By #6, Jan Robinson beat the engineer, so unless it was a game against themself, Robinson must be the pilot.
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Feb 8, 2021 19:29
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Correct! Puzzle #111: A Flock Of Martians Four Martians from different groups, the Uti, Grundi, Yomi, and Rafi, gathered for an intra-planetary conference to discuss the problem of the visiting Earthlings. AS was appropriate for diplomatic envoys, all were beautifully feathered in different colors: one re,d one green, one blue, and the fourth brown. Their names were Aken, Bal, Mun and Wora. 1. Before the meeting, the Uti had a pleasant breakfast with Mun. 2. After debating with the Martians in the blue and the brown feathers, Bal and the Yomi were so angry that they tore a wingful of feathers out of them before they were stopped. 3. Wora and the Rafi, however, agreed with the diplomat with the brown feathers, though they disagreed with the red-feathered Grundi. Who is the blue-feathered diplomat and to what group does he or she belong?
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Feb 12, 2021 03:13
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#111 The blue-feathered diplomat is Mun of the Rafi. Bal and the Yomi are not blue or brown, so they're green or red. Neither Wora nor the Rafi is brown. The Grundi is red, which means Bal is the Grundi, and the Yomi is green. The Rafi is not brown or green or red, so they're blue, and the Uti is brown. Wora has to be green or blue, so they're Rafi or Yomi... but Wora is not the Rafi, so they're the Yomi, and green. The Uti is not Mun, and Aken is the only one not given a group so far, so Aken is the Uti and brown, and Mun is the Rafi and blue. If your Uti is brown, consult a doctor immediately.
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Feb 12, 2021 04:10
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Correct! And we're on the final puzzle! And boy, it's a doozy. Puzzle #112: Aken's Friend On the day before the spaceship was to return to Earth, the Martians held a dinner party for the crew. In all there were eight at the table: Aken, Bal, Mun, Mark, Wora, Jones, Rider, and Smith. a. One was a history buff. b. One was a whiz at math. c. One was very tall. d. One was Aken's friend. e. One had yellow feathers. f. One was a pilot. g. One was a rock collector. h. One spoke a number of languages. 1. The person who was Aken's friend sat directly opposite Mark, the rock collector. 2. Wora sat between the math whiz and Aken's friend. 3. The tall one sat opposite Wora, with Aken to her left. 4. Smith, who had no real friends among the group, sat to the right of Mun who towered over the rest of the group. 5. The one who had yellow feathers sat opposite Bal, between Mun and the one who spoke a number of languages. 6. Jones was to the right of the rock collector and opposite the pilot who was next to Rider. Who was Aken's friend?
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Feb 14, 2021 19:29
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OK, let's take this one seriously. The description implies a round table. I'm going to represent it as two rows of 4: A B C D H G F E 1. The person who was Aken's friend sat directly opposite Mark, the rock collector. OK, so we have our starting table layout. We have: So Aken's friend is sitting at A, putting Mark, the rock collector at E. 2. Wora sat between the math whiz and Aken's friend. This one's a little fiddly, because there are a few different possibilities for Wora's position: In all cases: Aken's friend: A / Mark the rock collector: E Wora: B / math whiz: C or D Wora: C / math whiz: D Wora: H / math whiz: F or G Wora: G / math whiz: F Let's put a pin in that and come back to it. 3. The tall one sat opposite Wora, with Aken to her left. More possibilities: In all cases: Aken's friend: A / Mark the rock collector: E Wora: B / math whiz: C or D / tall one: F / Aken: G or H Wora: C / math whiz: D / tall one: G / Aken: H or B Wora: H / math whiz: F or G / tall one: D / Aken: F or G Wora: G / math whiz: F / tall one: C / Aken: D, or F 4. Smith, who had no real friends among the group, sat to the right of Mun who towered over the rest of the group. O-kay, so Mun is the 'tall one'. That's good to know. More importantly, Smith can't be Aken's friend. For those keeping track: Aken, Smith, Wora, Mark the rock collector, and the math whiz if they're a different person, can't be Aken's friend. Because Mun is the tall one and we've seen the possibilities for where they can sit, they aren't Aken's friend either. So we've narrowed things down to Bal, Jones, and Rider. In all cases: Aken's friend: A / Mark the rock collector: E Wora: B / math whiz: C or D / Mun the tall one: F / Aken: G or H / Smith: C or D Wora: C / math whiz: D / Mun the tall one: G / Aken: H or B / Smith: D or F Wora: H / math whiz: F or G / Mun the tall one: D / Aken: F or G / Smith: B or C Wora: G / math whiz: F / Mun the tall one: C / Aken: D or F / Smith: B or H 5. The one who had yellow feathers sat opposite Bal, between Mun and the one who spoke a number of languages. OK, I'm going to punt on this one and come back. 6. Jones was to the right of the rock collector and opposite the pilot who was next to Rider. OK, so Mark is the rock collector, so since he's at E, Jones must be at B, C, or D. This means that the pilot must be at F, G, or H, and Rider must be at F, G, H, or A (not E because Mark is sitting there). Critically, this removes Jones from consideration as Aken's friend. In all cases: Aken's friend: A / Mark the rock collector: E Wora: B / math whiz: C or D / Mun the tall one: F / Aken: G or H / Smith: C or D / Jones: C or D / pilot: G or H (assuming Mun isn't tall and a pilot) / Rider: A, G, or H Wora: C / math whiz: D / Mun the tall one: G / Aken: H or B / Smith: D or F / Jones: B or D / pilot: F or H / Rider: A (this case would make Rider Aken's friend). Wora: H / math whiz: F or G / Mun the tall one: D / Aken: F or G / Smith: B or C / Jones: B or C / pilot: F or G / Rider: F or G (this case would make Aken have to be the pilot). Wora: G / math whiz: F / Mun the tall one: C / Aken: D or F / Smith: B or H / Jones: B or D / pilot: F or H / Rider: A (this case would make Rider Aken's friend). So we have two cases where Rider is Aken's friend, and we can stop. What about the other two cases? 5. The one who had yellow feathers sat opposite Bal, between Mun and the one who spoke a number of languages. (again) So let's look at the two indeterminate cases... In all cases: Aken's friend: A / Mark the rock collector: E Wora: B / math whiz: C or D / Mun the tall one: F / Aken: G or H / Smith: C or D / Jones: C or D / pilot: G or H / Rider: A, G, or H Wora: H / math whiz: F or G / Mun the tall one: D / Aken: F or G / Smith: B or C / Jones: B or C / pilot: F or G / Rider: F or G (this case would make Aken have to be the pilot). So where can Bal sit? In the first case, it can't be B, C, D, E, or F. So it must be A, G, or H. The one with yellow feathers is thus at C, D, or E. Supposedly they're "between Mun and the one who spoke a number of languages". So (still in the first case), Mun is at F. If we assuming a narrow definition of 'between' ('right next to on either side'), then the language-speaker is at D and the one with yellow feathers is Mark the rock collector, at E. That would put Bal at A, and make Bal Aken's friend. This is probably not the case, because I'm going to implicitly assume for negation purposes that each person has only one characteristic. So the other possibility is that the yellow feather person is not at E, Bal is not at A, and the only remaining person who can be Aken's friend is Rider. So what about the second case? In this case, Bal can't sit at B, C, D, E, or H. They also can't be at F or G as then there'd be nowhere for Rider and Aken to sit. So they'd have to be at A and be Aken's friend. However... this would make E (Mark the rock collector) be the one with yellow feathers. Again, an impossibility. So, once the dust settles, Rider is Aken's friend. Phew!
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Feb 14, 2021 21:16
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#112 Aken's friend is Rider. Let's use the letter assignments the puzzle gives us for the 8 characters rather than their long descriptions, so we're looking for D. It's probably safe to assume D isn't Smith (#4) or Aken (since they're "Aken's friend"). We know G is Mark (#1) and C is Mun (#4). Wora isn't D or B (#2). Jones is to Mark's right and opposite F (#6), and D is opposite to Mark (#1), so Jones isn't D or B. We now know D isn't Jones or Wora, or Mark or Mun or Smith or Aken. So D is either Bal or Rider. But Bal is sitting opposite E (#5), and D is sitting opposite G, who is Mark (#1), so D has to be Rider. That was actually a lot simpler than I expected. Unless I got screwed up somewhere.
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Feb 15, 2021 05:21
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Double-posting, but where I said "Jones isn't D or B" I meant to put "Jones isn't D or F" but that doesn't change my answer.
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Feb 15, 2021 05:36
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| # ? May 4, 2024 08:31 |
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#112 Assumptions: The lettered statements each refer to unique individuals; that is, for each person, only one of the statements applies. Aken is not the person referred to as "Aken's friend". For seating descriptions, "opposite" is identical to "directly opposite". Likewise, "right", "left", or "between" imply a distance of fewer than four places. In Statement 4, the description of Mun indicates they are to be identified with statement c. To avoid having to say "the person identified in c", I'll just use those letters to refer to that individual. The question, then, is who is d? Aken - No (assumption that the two are not the same) Bal - No (By #5, e is opposite Bal, and by #1, g is opposite d) Mun - No (assumption of uniqueness, Mun is c by #4) Mark - No (By #1, also by uniqueness since Mark is g) Wora - No (By #2) Jones - No (By #6, Jones cannot be opposite Mark/g) Rider - Yes (especially bolstered if Jones is to the immediate right of Mark) Smith - No (By #4)
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Feb 15, 2021 20:45
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