|
Pawn 17 posted:I'm going to try to think back to HS physics class. I would use the x as a known (since we know the distance between the two buildings) and instead solve for y (the drop). Like if the drop was 16m instead of 15m like your assumption, that might be enough to get you over 50m traveled. You've got gravitational acceleration down as vertical velocity. x=x0+vx0t+.5axt2 y=y0+vy0t+.5ayt2 x is distance between buildings x0 is 0 vx0 is how fast you want to go at takeoff ax is 0 unless you want to get fancy and include drag (in the negative) based on the frontal area of the car y0 is 0 vy0 is 0 ay is -9.8m/s^2 Your unknowns are t and y, and you have 2 equations to solve for them. If y is greater than however high you think the car jumps from, it'd have hit the ground before reaching the other tower. mobby_6kl posted:WRONG! Did these guys get enough distance to go between buildings though??
|
# ¿ Oct 14, 2016 01:12 |
|
|
# ¿ May 4, 2024 02:09 |